The numerator of a fraction is multiple of two numbers. One of the numbers is greater than the other by 2. The greater number is smaller than the denominator by 4. If the denominator 7 + C (C > - 7) is a constant, then the minimum value of the fraction is:
A. 5
B. 1/5
C. -5
D. -1/5
Answer: Option D
Solution(By Examveda Team)
According to the given conditionDenominator = 7 + C [C > -7]
\[\begin{array}{*{20}{c}} {{\text{Denominator}} = }&{{\text{Greator number}}}&{}&{{\text{Smaller number}}} \\ {}&{\left( {7 + C - 4} \right)}& \times &{\left( {7 + C - 4 - 2} \right)} \end{array}\]
Equation $$ = \frac{{\left( {3 + C} \right)\left( {1 + C} \right)}}{{7 + C}}$$
By putting value according to option
C = -2 for minimum value
= -1/5
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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