Examveda

The Nyquist filter has impulse response given by

A. $$h\left( t \right) = \frac{{\sin \left( {\frac{{\pi t}}{T}} \right)}}{{\left( {\frac{{\pi t}}{T}} \right)}}$$

B. $$h\left( t \right) = \frac{1}{2}\left( {\frac{{\sin \left( {\pi t} \right)}}{{\pi t}}} \right)$$

C. $$h\left( t \right) = \frac{{\sin \left( {\pi t} \right)}}{{\left( {\frac{{\pi t}}{T}} \right)}}$$

D. $$h\left( t \right) = \frac{{\cos \left( {\pi t} \right)}}{{\left( {\frac{{\pi t}}{T}} \right)}}$$

Answer: Option A


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