The operating temperature of a cold storage is -2°C. The heat leakage from the surrounding is 30 kW for the ambient temperature of 40°C. The actual C.O.P. of refrigeration plant used is one fourth that of ideal plant working between the same temperatures. The power required to drive the plant is
A. 1.86 kW
B. 3.72 kW
C. 7.44 kW
D. 18.6 kW
Answer: Option D
We know COP = TEMP OF COLD BODY/TEMP OF HOT BODY - TEMP OF COLD BODY.
So here COP = 271/(313-271) = 6.45.
Actual COP = 1/4th of Ideal COP = 1/4(6.45) = 1.6125.
We also know actual COP = Heat extracted/Work input.
1.6125 = 30/WI.
Therefore Power = 30/1.6125 = 18.6 K