The polar moment of inertia of a solid circular shaft of diameter (D) is
A. $$\frac{{\pi {{\text{D}}^3}}}{{16}}$$
B. $$\frac{{\pi {{\text{D}}^3}}}{{32}}$$
C. $$\frac{{\pi {{\text{D}}^4}}}{{32}}$$
D. $$\frac{{\pi {{\text{D}}^4}}}{{64}}$$
Answer: Option C
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