The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:

A. 4.37%

B. 5%

C. 6%

D. 8.75%

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & {\text{Increase}}\,{\text{in}}\,{\text{10}}\,{\text{years}} \cr & = {262500 - 175000} \cr & = 87500 \cr & {\text{Increase}}\% \cr & = \left( {\frac{{87500}}{{175000}} \times 100} \right)\% = 50\% \cr & \therefore {\text{Required}}\,{\text{average}} \cr & = {\frac{{50}}{{10}}} \% = 5\% \cr} $$