The present age of Mr. Sanyal is three times the age of his son. Six years hence , the ratio of their ages will be 5 : 2. What is the present age of Mr. Sanyal ?
A. 48 years
B. 50 years
C. 54 years
D. 60 years
E. None of these
Answer: Option C
Solution(By Examveda Team)
Let the son's age be $$x$$ years ,Then Mr. Sanyal's age = 3$$x$$ years
$$\eqalign{ & \therefore \frac{{3x + 6}}{{x + 6}} = \frac{5}{2} \cr & \Rightarrow 2\left( {3x + 6} \right) = 5\left( {x + 6} \right) \cr & \Rightarrow 6x + 12 = 5x + 30 \cr & \Rightarrow x = 18 \cr} $$
∴ Present age of Mr. Sanyal = 3x years
= (3 × 18) years
= 54 years
Related Questions on Problems on Ages
A. 2 times
B. $$2\frac{1}{2}\,{\text{times}}$$
C. $$2\frac{3}{4}\,{\text{times}}$$
D. 3 times
A. 4 years
B. 8 years
C. 10 years
D. None of these
A. 14 years
B. 19 years
C. 33 years
D. 38 years
Join The Discussion