The present ratio of ages of A and B is 4 : 5. 18 years ago, this ratio was 11 : 16. Find the sum total of their present ages.

A. 90 years

B. 105 years

C. 110 years

D. 80 years

E. 95 years

Answer: Option A

Solution(By Examveda Team)

Let present age of A and B be 4x and 5x
18 years ago their ages
$$\frac{{4x - 18}}{{5x - 18}} = \frac{{11}}{{16}}$$
Or, 64x - 288 = 55x - 198
Or, 64x - 55x = -198 + 288
Or, 9x = 90
Or, x = $$\frac{{90}}{9}$$ = 10
Sum of the present ages = 40 + 50 = 90 years