The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
A. 101
B. 107
C. 111
D. 185
Answer: Option C
Solution(By Examveda Team)
Let the numbers be 37a and 37bThen, 37a x 37b = 4107
⇒ ab = 3
Now, co-primes with product 3 are (1, 3)
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111)
∴ Greater number = 111
This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M
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Related Questions on Problems on H.C.F and L.C.M
directly divided to 4107/37=111 ie our answer
37a × 37b=4107 -> ab =3
How ab=3 comes?
Explain please
I didn't understand this.... My question is 4107÷37÷3= 4107÷(37×3)
Its simple gyus...= 4170/37*37
=4170/1369(divide those numbers)
=3.
a=37*1=37(smallest number)
b=37*3=111(largest number)
37a × 37b=4107 and ab =3 how ...plss explain clearly
ab comes to be 111 how is it 3 ?
Full solve this sum plz..I have few doudts
No common factors other than 1.
21 and 22 are coprime:
• The factors of 21 are 1, 3, 7 and 21
• The factors of 22 are 1, 2, 11 and 22
(the only common factor is 1)
But 21 and 24 are NOT coprime:
• The factors of 21 are 1, 3, 7 and 21
• The factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24
(the common factors are 1 AND 3)
Also called "relatively prime" or "mutually prime".
what is co-prime?