The ratio of water and milk in a 30 liter mixture is 7 : 3. Find the quantity of water to be added to the mixture in order to make this ratio 6 : 1.
A. 30
B. 32
C. 33
D. 35
Answer: Option C
A. 30
B. 32
C. 33
D. 35
Answer: Option C
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
B. 3 : 4 : 5
C. 4 : 5 : 6
D. 9 : 8 : 10
ratio 7 = water
ratio 3 = milk
total ratio (10) = 30 liters
so, 30--------------10 (for milk)
m -------------- 3 (cross multiply)
30 x 3 = m(10)
milk=9
water =21 liters
let x amount of water added to mixture and new ratio is 6 : 1
so, water milk
21+x : 9
6 : 1
(21+x) 1 = 6 x 9
21+x = 54
x=33 ANSWER
The previous ratio is 7:3 now,
Quantity of water in mixture= 30*7/10=21
Quantity of milk in mixture=30*3/10=9
The new ratio is 6:1
So, let water added=x
According to new ratio,
(21+x)/9=6/1
21+x=54
x=33
The extra water added is 33 liters.
when 1 liter of water is added to a mixture of milk and water,the new mixture contains 20% milk.when 1 liter of milk is added to the new mixture the resulting mixture contains 33 % milk.the % of milk in the original mixture was?
i dont understand this solution