The reduced levels of points, 30 metres apart along the longitudinal section of a road portion between chainages 5 and 9 are shown in the given figure. If there is a uniform up-gradient of the road 120 in 1, the chainage of the point with no filling or cutting is
A. (6 + 15) chains
B. (6 + 12) chains
C. (6 + 18) chains
D. None of these
Answer: Option B
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The expected out turn of 12 mm plastering with cement mortar is
A. 2.5 sq m
B. 4.0 sq m
C. 6.0 sq m
D. 8.0 sq m
A. Excavation
B. Surface dressing
C. Cutting
D. Surface excavation
Gradient given is 1:120
So for 30m rise of = (1/120*30),
= 0.25 m.
RL of formation level @6 chain = 100.0 + 0.25.
= 100.25 m.
RL of formation level @7 chain = 100.25+ 0.25
=100.5 m.
So difference = 102-100.5 = 1.5.
By similar triangles -
(1/x) = 1.5/(30-x)
X = 12.
So the answer is (6+12) chains.
How? Please solve.