The remainder of $$\frac{{{2^{59}}}}{{255}}$$ is:
A. 55
B. 56
C. 0
D. 2
E. None of these
Answer: Option E
Solution(By Examveda Team)
$$\eqalign{ & {2^{59}}\,{\text{can}}\,{\text{be}}\,{\text{expressed}}\,{\text{as}}\,{2^{8n}} \cr & {\text{So}}, \cr & {\text{Remainder}}\,\frac{{{2^{59}}}}{{255}} \cr & = {\text{Remainder}}\,\frac{{{2^{8n}}}}{{255}} \cr & = {\text{Remainder}}\,\frac{{{{256}^n}}}{{255}} = 1 \cr & {\text{Required}}\,{\text{remainder}} = 1 \cr} $$Join The Discussion
Comments ( 7 )
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
The required remainder is 8 not 1. Please don't set wrong answers it's already very confusing
Option E is Correct but Answer must be 8.
59(8*7+3) is not a multiple of 8.
Yeah 8 is correct guys
Correct answer is 8
Correct answer is 1. Please check your calculation.
Given answer is wrong. The correct answer will be 8.
ans would be 8.