The remainder of $$\frac{{{6^{36}}}}{{215}}:$$
A. 0
B. 1
C. 2
D. 3
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & \frac{{ {{6^{36}}} }}{{215}},\,{\text{can}}\,{\text{be}}\,{\text{written}}\,{\text{as}} \cr & \frac{{{{\left( {{6^3}} \right)}^{12}}}}{{215}} \cr & Or,\,\frac{{{{216}^{12}}}}{{215}},\,[216\,{\text{on}}\,{\text{divided}}\,{\text{by}}\,215,\,{\text{gives}}\,{\text{remainder}}\,1] \cr & \frac{{{1^{12}}}}{{215}} \cr & {\text{The}}\,{\text{remainder}}\,{\text{will}}\,{\text{be}}\,1 \cr} $$Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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