?
The remainder of $$\frac{{{6^{36}}}}{{215}}:$$
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& \frac{{ {{6^{36}}} }}{{215}},\,{\text{can}}\,{\text{be}}\,{\text{written}}\,{\text{as}} \cr
& \frac{{{{\left( {{6^3}} \right)}^{12}}}}{{215}} \cr
& Or,\,\frac{{{{216}^{12}}}}{{215}},\,[216\,{\text{on}}\,{\text{divided}}\,{\text{by}}\,215,\,{\text{gives}}\,{\text{remainder}}\,1] \cr
& \frac{{{1^{12}}}}{{215}} \cr
& {\text{The}}\,{\text{remainder}}\,{\text{will}}\,{\text{be}}\,1 \cr} $$
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