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The remainder , when (1523 + 2323) is divided by 19, is

A. 4

B. 15

C. 0

D. 18

Answer: Option C

Solution(By Examveda Team)

NOTE: an + bn is always divisible by (a + b) when n is odd.

So, (1523 + 2323) always divisible by 38.
And 38 is a multiple of 19, So, the number which is divisible by 38, is divisible by 19 too.
(1523 + 2323) is divisible by 19.
So, $$\frac{{{{15}^{23}} + {{23}^{23}}}}{{19}}$$   == Remainder ⇒ $$\frac{{15 + 23}}{{19}}$$  == Remainder ⇒ $$\frac{{38}}{{19}}$$ == Remainder ⇒ 0

This Question Belongs to Arithmetic Ability >> Number System

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Comments ( 2 )

  1. Manas Ranjan
    Manas Ranjan :
    3 years ago

    Only odd numbers or same odd numbers sir ?

  2. Md. Mahmudul
    Md. Mahmudul :
    6 years ago

    What if n is even ?

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