The remainder , when (1523 + 2323) is divided by 19, is
A. 4
B. 15
C. 0
D. 18
Answer: Option C
Solution(By Examveda Team)
NOTE: an + bn is always divisible by (a + b) when n is odd.So, (1523 + 2323) always divisible by 38.
And 38 is a multiple of 19, So, the number which is divisible by 38, is divisible by 19 too.
(1523 + 2323) is divisible by 19.
So, $$\frac{{{{15}^{23}} + {{23}^{23}}}}{{19}}$$ == Remainder ⇒ $$\frac{{15 + 23}}{{19}}$$ == Remainder ⇒ $$\frac{{38}}{{19}}$$ == Remainder ⇒ 0
Join The Discussion
Comments ( 2 )
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
Only odd numbers or same odd numbers sir ?
What if n is even ?