The residue of $${\text{f}}\left( {\text{z}} \right) = \frac{{{{\text{z}}^3}}}{{{{\left( {{\text{z}} - 1} \right)}^4}\left( {{\text{z}} - 2} \right)\left( {{\text{z}} - 3} \right)}}$$ at z = 3 is
A. -8
B. $$\frac{{101}}{{16}}$$
C. 0
D. $$\frac{{27}}{{16}}$$
Answer: Option D
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