The residue of the function $${\text{f}}\left( {\text{z}} \right) = \frac{1}{{{{\left( {{\text{z}} + 2} \right)}^2}{{\left( {{\text{z}} - 2} \right)}^2}}}$$ at z = 2 is
A. $$ - \frac{1}{{32}}$$
B. $$ - \frac{1}{{16}}$$
C. $$\frac{1}{{16}}$$
D. $$\frac{1}{{32}}$$
Answer: Option A
Related Questions on Complex Variable
A. -x2 + y2 + constant
B. x2 - y2 + constant
C. x2 + y2 + constant
D. -(x2 + y2) + constant
The product of complex numbers (3 - 2i) and (3 + i4) results in
A. 1 + 6i
B. 9 - 8i
C. 9 + 8i
D. 17 + 6i
If a complex number $${\text{z}} = \frac{{\sqrt 3 }}{2} + {\text{i}}\frac{1}{2}$$ then z4 is
A. $$2\sqrt 2 + 2{\text{i}}$$
B. $$\frac{{ - 1}}{2} + \frac{{{\text{i}}{{\sqrt 3 }^2}}}{2}$$
C. $$\frac{{\sqrt 3 }}{2} - {\text{i}}\frac{1}{2}$$
D. $$\frac{{\sqrt 3 }}{2} - {\text{i}}\frac{1}{8}$$
A. 2πnj
B. 0
C. $$\frac{{\pi {\text{j}}}}{{2\pi }}$$
D. 2πn
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