The residues of a complex function $${\text{X}}\left( {\text{z}} \right) = \frac{{1 - 2{\text{z}}}}{{{\text{z}}\left( {{\text{z}} - 1} \right)\left( {{\text{z}} - 2} \right)}}$$ at its poles are
A. $$\frac{1}{2},\, - \frac{1}{2}{\text{ and }}1$$
B. $$\frac{1}{2},\,\frac{1}{2}{\text{ and }} - 1$$
C. $$\frac{1}{2},\,1{\text{ and }} - \frac{3}{2}$$
D. $$\frac{1}{2},\, - 1{\text{ and }}\frac{3}{2}$$
Answer: Option C
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