The root locus plot of the roots of the characteristics equation of a closed loop system having the open loop transfer function $$\frac{{{\text{K}}\left( {{\text{s}} + 1} \right)}}{{2\left( {2{\text{s}} + 1} \right)\left( {3{\text{s}} + 1} \right)}}$$ will have a definite number of loci for variation of K from 0 to $$\infty $$. The number of loci is
A. 1
B. 3
C. 4
D. 2
Answer: Option B
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We are given the open-loop transfer function:
πΊ
(
π
)
π»
(
π
)
=
πΎ
(
π
+
1
)
2
(
2
π
+
1
)
(
3
π
+
1
)
G(s)H(s)=
2(2s+1)(3s+1)
K(s+1)
β
Letβs analyze it step by step:
Step 1: Simplify the Transfer Function
πΊ
(
π
)
π»
(
π
)
=
πΎ
(
π
+
1
)
6
(
π
+
0.5
)
(
π
+
1
3
)
G(s)H(s)=
6(s+0.5)(s+
3
1
β
)
K(s+1)
β
Step 2: Determine Poles and Zeros
Poles: From the denominator:
π
=
β
0.5
s=β0.5
π
=
β
1
3
s=β
3
1
β
Zero: From the numerator:
π
=
β
1
s=β1
So:
Number of poles = 2
Number of zeros = 1
Step 3: Number of Root Locus Branches (Loci)
The number of loci (root locus branches) is always equal to the number of poles of the open-loop transfer function.
Thus, the number of loci = 2
β Final Answer: D. 2
solution plz