Examveda

The series \[\sum\limits_{{\text{m}} = 0}^\infty {\frac{1}{{{4^{\text{m}}}}}{{\left( {{\text{x}} - 1} \right)}^{2{\text{m}}}}} \]   converges for

A. -2 < X < 2

B. -1 < X < 3

C. -3 < X < 1

D. X < 3

Answer: Option B


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