The solution of the differential equation for \[y\left( t \right):\frac{{{d^2}y}}{{d{t^2}}} - y = 2\cosh \left( t \right),\] subject to the initial conditions y(0) = 0 and \[{\left. {\frac{{dy}}{{dt}}} \right|_{t = 0}} = 0\] is
A. \[\frac{1}{2}\] cosh(t) + t sinh(t)
B. -sinh(t) + t cosh(t)
C. t cosh(t)
D. t sinh(t)
Answer: Option D


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