The solution of the system of differential equations \[\frac{{dy}}{{dx}} = y - z\] and \[\frac{{dz}}{{dx}} = - 4y + z\] is given by (for A and B are arbitrary constants)
A. y(x) = Ae3x + Be-x; z(x) = -2Ae3x + 2Be-x
B. y(x) = Ae3x + Be-x; z(x) = 2Ae3x + 2Be-x
C. y(x) = Ae3x + Be-x; z(x) = 2Ae3x - 2Be-x
D. y(x) = Ae3x + Be-x; z(x) = -2Ae3x - 2Be-x
Answer: Option A


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