The solution to the system of equations is \[\left[ {\begin{array}{*{20}{c}} 2&5 \\ { - 4}&3 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {\text{x}} \\ {\text{y}} \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} 2 \\ { - 30} \end{array}} \right]\]
A. 6, 2
B. -6, 2
C. -6, -2
D. 6, -2
Answer: Option D
Related Questions on Linear Algebra
A. 3, 3 + 5j, 6 - j
B. -6 + 5j, 3 + j, 3 - j
C. 3 + j, 3 - j, 5 + j
D. 3, -1 + 3j, -1 - 3j
A. 1024 and -1024
B. 1024√2 and -1024√2
C. 4√2 and -4√2
D. 512√2 and -512√2

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