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The sum and products of two numbers are 12 and 35 respectively. The sum of their reciprocals will be:

A. $$\frac{1}{3}$$

B. $$\frac{1}{5}$$

C. $$\frac{{12}}{{35}}$$

D. $$\frac{{35}}{{12}}$$

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & {\text{Let}}\,{\text{two}}\,{\text{numbers}}\,{\text{are}}\,x\,{\text{and}}\,y. \cr & {\text{Now,}}\,{\text{Sum}}\,{\text{of}}\,{\text{the}}\,{\text{numbers}}, \cr & x + y = 12 \cr & {\text{Product}}\,{\text{of}}\,{\text{the}}\,{\text{number}}, \cr & xy = 35 \cr & {\text{Then}}\,{\text{sum}}\,{\text{of}}\,{\text{the}}\,{\text{reciprocals}} \cr & = {\frac{1}{x}} + {\frac{1}{y}} \, \cr & = \frac{{ {x + y} }}{{xy}} \cr & = \frac{{12}}{{35}} \cr} $$

This Question Belongs to Arithmetic Ability >> Number System

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