The sum of four consecutive two-digit odd numbers, when divided by 10, become a perfect square. Which of the following can possibly be one of these four numbers?
A. 21
B. 25
C. 41
D. 67
E. 73
Answer: Option C
Solution(By Examveda Team)
Using options,We find that four consecutive odd numbers are 37, 39, 41 and 43
The sum of these 4 numbers is 160, when divided by 10 we get 16 which is a perfect square.
Thus, 41 is one of the odd numbers
This Question Belongs to Arithmetic Ability >> Number System
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Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
21+22+23+24= 90
90/10= 9 is also a perfect squire of 3.
So option A also correct.
Please solve this without going through options