The sum of squares of three positive integers is 323. If the sum of squares of two numbers is twice the third, their product is :
A. 255
B. 260
C. 265
D. 270
Answer: Option A
Solution(By Examveda Team)
Let the integers in a, b, ca2 + b 2 + c2 = 323.....(i)
a2 + b2 + = 2c.....(ii)
Break the 323 in to their squares
a = 5
b = 3
c = 17
So, a2 + b2 + c2 = 323
and
a2 + b2 = 2c
252 + 32 = 2 × 17
34 = 34
So, Satisfied
a : b : c = 17 × 5 × 3 = 255
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
Join The Discussion