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The sum of squares of three positive integers is 323. If the sum of squares of two numbers is twice the third, their product is :
Answer & Solution
Correct Answer:
Option
A
Let the integers in a, b, c
a2 + b 2 + c2 = 323.....(i)
a2 + b2 + = 2c.....(ii)
Break the 323 in to their squares
a = 5
b = 3
c = 17
So, a2 + b2 + c2 = 323
and
a2 + b2 = 2c
252 + 32 = 2 × 17
34 = 34
So, Satisfied
a : b : c = 17 × 5 × 3 = 255
a2 + b 2 + c2 = 323.....(i)
a2 + b2 + = 2c.....(ii)
Break the 323 in to their squares
a = 5
b = 3
c = 17
So, a2 + b2 + c2 = 323
and
a2 + b2 = 2c
252 + 32 = 2 × 17
34 = 34
So, Satisfied
a : b : c = 17 × 5 × 3 = 255
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