The sum of the cubes of two numbers in the ratio 3 : 4 is 5824. The sum of the numbers is :
A. $${\left( {5824} \right)^{\frac{1}{3}}}$$
B. 28
C. 24
D. 14
Answer: Option B
Solution (By Examveda Team)
Let numbers are = 3x, 4x(3x)3 + (4x)3 = 5824
27x3 + 64x3 = 5824
91x3 = 5824
x3 = $$\frac{5824}{91}$$
x3 = 64
x = 4
So, numbers are
3x = 3 × 4 = 12
4x = 4 × 4 = 16
Sum = 12 + 16 = 28
This Question Belongs to Arithmetic Ability >> Number System
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