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The sum of the digits of a 3-digit number is subtracted from the number. The resulting number is always :
Answer & Solution
Correct Answer:
Option
B
Let the hundreds, tens and unit digits be x, y and z respectively.
Then,
(100x + 10y + z) - (x + y + z)
= 99x + 9y
= 9 (11x + y)
So, the resulting number is divisible by 9
Then,
(100x + 10y + z) - (x + y + z)
= 99x + 9y
= 9 (11x + y)
So, the resulting number is divisible by 9
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