The sum of the digits of a two digit number is $$\frac{1}{7}$$ of the number. The units digit is 4 less than the tens digit. If the number obtained on reversing its digits is divided by 7, the remainder will be:

Solution (By Examveda Team)

$$\eqalign{ & x + y = \frac{1}{7}\left( {10x + y} \right) \cr & 7x + 7y = 10x + y \cr & 3x = 6y \cr & x:y = 2:1 \cr & 1{\text{ unit}} \to {\text{4}} \cr & {\text{Number will be}} = 84 \cr & \frac{{48}}{7}R \to 6 \cr} $$