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The sum of the digits of a two digit number is $$\frac{1}{7}$$ of the number. The units digit is 4 less than the tens digit. If the number obtained on reversing its digits is divided by 7, the remainder will be:
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& x + y = \frac{1}{7}\left( {10x + y} \right) \cr
& 7x + 7y = 10x + y \cr
& 3x = 6y \cr
& x:y = 2:1 \cr
& 1{\text{ unit}} \to {\text{4}} \cr
& {\text{Number will be}} = 84 \cr
& \frac{{48}}{7}R \to 6 \cr} $$
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