The sum of the digits of two-digit number is 10, while when the digits are reversed, the number decrease by 54. Find the changed number.
A. 28
B. 19
C. 37
D. 46
E. 82
Answer: Option A
Solution(By Examveda Team)
Let number be (10x + y) According to question, (10x + y) - (10y + x) = 54 10x - 10y + y - x = 54 Or, 9x - 9y = 54 Or, x - y = 6 -------(i) Sum of digits, (x + y) = 10 ------- (ii) (i) - (ii) So, x - y - x - y = 6 - 10 Or, -2y = -4 Or, y = 2 and, x = 8 Then, the required number is = (10y + x)= 10 × 2 + 8
= 28
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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