The sum of the numerator and denominator of a positive fraction is 11. If 2 is added to both numerator and denominator, the fraction is increased by $$\frac{1}{{24}}$$. The difference of numerator and denominator of the fraction is -

Solution(By Examveda Team)

Let the numerator and denominator br x and 11 - x
According to question,
$$\eqalign{ & {\text{Fraction }} = \frac{x}{{11 - x}} \cr & \Rightarrow \frac{{x + 2}}{{11 - x + 2}} = \frac{x}{{11 - x}} + \frac{1}{{24}} \cr & \Rightarrow \frac{{x + 2}}{{13 - x}} - \frac{x}{{11 - x}} = \frac{1}{{24}} \cr} $$
$$ \Rightarrow \frac{{11x + 22 - {x^2} - 2x - 13x + {x^2}}}{{\left( {13 - x} \right)\left( {11 - x} \right)}}$$       $$ = \frac{1}{{24}}$$
$$\eqalign{ & \Rightarrow \frac{{22 - 4x}}{{143 - 24x + {x^2}}} = \frac{1}{{24}} \cr & \Rightarrow 528 - 96x = 143 - 24x + {x^2} \cr & \Rightarrow {x^2} + 72x - 385 = 0 \cr & \Rightarrow \left( {x + 77} \right)\left( {x - 5} \right) = 0 \cr & \Rightarrow x = 5 \cr & {\text{Numerator }}(x) = 5 \cr & {\text{Denominator }} = 11 - 5 = 6 \cr & {\text{Difference }} = 6 - 5 = 1 \cr} $$