The sum of three consecutive odd natural numbers each divisible by 3 is 63. What is the largest among them ?

Solution (By Examveda Team)

$$\eqalign{ & \left( x \right) + \left( {x + 6} \right) + \left( {x + 12} \right) = 63 \cr & 3x + 18 = 63 \cr & 3x = 45 \cr & x = 15 \cr & {\text{So,the largest number is}} \cr & {\text{ = }}15 + 12 \cr & = 27 \cr} $$