The system of equations
x + y + z = 6
x + 4y + 6z = 20
x + 4y + \[\lambda \]z = \[\mu \]
has NO solution for values of \[\lambda \] and \[\mu \] given by
A. \[\lambda = 6,\,\mu = 20\]
B. \[\lambda = 6,\,\mu \ne 20\]
C. \[\lambda \ne 6,\,\mu = 20\]
D. \[\lambda \ne 6,\,\mu \ne 20\]
Answer: Option B
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