Examveda

The system of equations
x + y + z = 6
x + 4y + 6z = 20
x + 4y + \[\lambda \]z = \[\mu \]
has NO solution for values of \[\lambda \] and \[\mu \] given by

A. \[\lambda = 6,\,\mu = 20\]

B. \[\lambda = 6,\,\mu \ne 20\]

C. \[\lambda \ne 6,\,\mu = 20\]

D. \[\lambda \ne 6,\,\mu \ne 20\]

Answer: Option B


This Question Belongs to Engineering Maths >> Linear Algebra

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