The total number of atoms in 8.5 gm of NH3 is __________ × 1023.
A. 9.03
B. 3.01
C. 12.04
D. 6.02
Answer: Option C
Solution (By Examveda Team)
The molecular weight of NH3 is 17 g/mol (Nitrogen = 14, Hydrogen = 1 × 3 = 3).For 8.5 grams of NH3, the number of moles is calculated as:
Moles of NH3 = 8.5 / 17 = 0.5 moles.
The total number of molecules in 0.5 moles is:
0.5 × 6.02 × 1023 molecules.
Since each molecule of NH3 contains 4 atoms (1 nitrogen and 3 hydrogen), the total number of atoms is:
0.5 × 6.02 × 1023 × 4 = 12.04 × 1023 atoms.
This Question Belongs to Chemical Engineering >> Stoichiometry
B is correct answer
12.o4 option c.. no one is right however
3.01*4=12.04
3.01 are molecules and four atoms present there. one N and three H. multiplying both gives total nmber of atoms
The molar mass of NH3 is equals to 17 gram.
Moles of NH3 in 8.5 gm =8.5/17=0.5
thus molecules in half mole NH3 is 6.022×10^23×0.5
and atoms in half mole NH3=0.5× 6.022×10^23×4
now calculate it
I think this is wrong .. Cause ... Guiven mass /molar mass*6.02*10^23 * atoms is the formula
= 8.5/17×6.02×10^23× 4 [1 H & 3N]
=3.01×4 = 12.04.m option B should be ri8 .. Printing mistake..
Wrong ans
Correct answer is B.
No.of moles of NH3= 8.5/17 =0.5
1mole = 6.022×10^23 atoms
0.5mole= 0.5×6.022×10^23=3.011×10^23
Any one explain this pb
Please explain the solution.