The total number of atoms in 8.5 gm of NH₃ is __________ × 10²³.

12.o4 option c.. no one is right however
3.01*4=12.04
3.01 are molecules and four atoms present there. one N and three H. multiplying both gives total nmber of atoms

The molar mass of NH3 is equals to 17 gram.
Moles of NH3 in 8.5 gm =8.5/17=0.5
thus molecules in half mole NH3 is 6.022×10^23×0.5

and atoms in half mole NH3=0.5× 6.022×10^23×4
now calculate it

I think this is wrong .. Cause ... Guiven mass /molar mass*6.02*10^23 * atoms is the formula
= 8.5/17×6.02×10^23× 4 [1 H & 3N]
=3.01×4 = 12.04.m option B should be ri8 .. Printing mistake..

Wrong ans

Correct answer is B.
No.of moles of NH3= 8.5/17 =0.5
1mole = 6.022×10^23 atoms
0.5mole= 0.5×6.022×10^23=3.011×10^23

Any one explain this pb

Please explain the solution.