The two links OA and OB are connected by a pin joint at O. If the link OA turns with angular velocity $${\omega _1}$$ rad/s in the clockwise direction and the link OB turns with angular velocity $${\omega _2}$$ rad/s in the anticlockwise direction, then the rubbing velocity at the pin joint O is (where r = Radius of the pin at O)
A. $${\omega _1}{\omega _2}{\text{r}}$$
B. $$\left( {{\omega _1} - {\omega _2}} \right){\text{r}}$$
C. $$\left( {{\omega _1} + {\omega _2}} \right){\text{r}}$$
D. $$\left( {{\omega _1} - {\omega _2}} \right)2{\text{r}}$$
Answer: Option C
=> B. is the correct answer. [not C]
exp,
link 1 - cw(+ve) omega1
link 2 - acw(-ve) omega2
r = radius of pin
so, we know that
Vr = r (omega1 - omega2) # {Vr - rubbing velocity}
Vr = r ( omega12 )