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The two links OA and OB are connected by a pin joint at O. If the link OA turns with angular velocity $${\omega _1}$$ rad/s in the clockwise direction and the link OB turns with angular velocity $${\omega _2}$$ rad/s in the anticlockwise direction, then the rubbing velocity at the pin joint O is (where r = Radius of the pin at O)

A. $${\omega _1}{\omega _2}{\text{r}}$$

B. $$\left( {{\omega _1} - {\omega _2}} \right){\text{r}}$$

C. $$\left( {{\omega _1} + {\omega _2}} \right){\text{r}}$$

D. $$\left( {{\omega _1} - {\omega _2}} \right)2{\text{r}}$$

Answer: Option C


This Question Belongs to Mechanical Engineering >> Theory Of Machine

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Comments ( 1 )

  1. ARJUN L
    ARJUN L :
    9 months ago

    => B. is the correct answer. [not C]
    exp,
    link 1 - cw(+ve) omega1
    link 2 - acw(-ve) omega2
    r = radius of pin
    so, we know that
    Vr = r (omega1 - omega2) # {Vr - rubbing velocity}
    Vr = r ( omega12 )

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