The value of $$\left( {1\frac{1}{3} \div 2\frac{6}{7}{\text{ of }}5\frac{3}{5}} \right) \div \left( {6\frac{2}{5} \div 4\frac{1}{2}{\text{ of}}\,5\frac{1}{3}} \right) \times \left( {\frac{3}{4} \times 2\frac{2}{3} \div \frac{5}{9}{\text{ of }}1\frac{1}{5}} \right) = 1 + {\text{k}},$$             where k lies between:

A. -0.07 and -0.06

B. -0.08 and -0,07

C. -0.06 and -0.05

D. -0.5 and -0.04

Answer: Option A