The value of $$\frac{{3\left( {{\text{cose}}{{\text{c}}^2}{{26}^ \circ } - {{\tan }^2}{{64}^ \circ }} \right) + \left( {{{\cot }^2}{{42}^ \circ } - {{\sec }^2}{{48}^ \circ }} \right)}}{{\cot \left( {{{22}^ \circ } - \theta } \right) - {\text{cose}}{{\text{c}}^2}\left( {{{62}^ \circ } + \theta } \right) - \tan \left( {\theta + {{68}^ \circ }} \right) + {{\tan }^2}\left( {{{28}^ \circ } - \theta } \right)}}\,{\text{is:}}$$
A. 4
B. -2
C. 3
D. -1
Answer: Option B
Solution (By Examveda Team)
$$\eqalign{ & \frac{{3\left( {{\text{cose}}{{\text{c}}^2}{{26}^ \circ } - {{\tan }^2}{{64}^ \circ }} \right) + \left( {{{\cot }^2}{{42}^ \circ } - {{\sec }^2}{{48}^ \circ }} \right)}}{{\cot \left( {{{22}^ \circ } - \theta } \right) - {\text{cose}}{{\text{c}}^2}\left( {{{62}^ \circ } + \theta } \right) - \tan \left( {\theta + {{68}^ \circ }} \right) + {{\tan }^2}\left( {{{28}^ \circ } - \theta } \right)}} \cr & = \frac{{3\left( {{\text{cose}}{{\text{c}}^2}{{26}^ \circ } - {{\cot }^2}{{26}^ \circ }} \right) + \left( {{{\cot }^2}{{42}^ \circ } - {\text{cose}}{{\text{c}}^2}{{42}^ \circ }} \right)}}{{\cot \left( {{{22}^ \circ } - \theta } \right) - {\text{cose}}{{\text{c}}^2}\left( {{{62}^ \circ } + \theta } \right) - \cot \left( {{{22}^ \circ } + \theta } \right) + {{\cot }^2}\left( {{{62}^ \circ } + \theta } \right)}} \cr & = \frac{{3 \times 1 + \left( { - 1} \right)}}{{ - 1}} \cr & = - 2 \cr} $$This Question Belongs to Arithmetic Ability >> Trigonometry
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