The value of 8(sin6θ + cos6θ) - 12(sin4θ + cos4θ) is equal to?
A. 20
B. -20
C. -4
D. 4
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & {\text{8}}\left( {{{\sin }^6}\theta + {\text{co}}{{\text{s}}^6}\theta } \right) - {\text{12}}\left( {{{\sin }^4}\theta + {\text{co}}{{\text{s}}^4}\theta } \right) \cr & {\text{Put }}\theta = {0^ \circ } \cr & = 8\left( {{{\sin }^6}{0^ \circ } + {{\cos }^6}{0^ \circ }} \right) - 12\left( {{{\sin }^4}{0^ \circ } + {{\cos }^4}{0^ \circ }} \right) \cr & = 8\left( {0 + 1} \right) - 12\left( {0 + 1} \right) \cr & = - 4 \cr} $$Related Questions on Trigonometry
A. x = -y
B. x > y
C. x = y
D. x < y
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