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The value of coses260° + sec260° - cot260° + tan230° will be?

A. 5

B. $${\text{5}}\frac{1}{2}$$

C. $${\text{5}}\frac{2}{3}$$

D. $${\text{5}}\frac{1}{3}$$

Answer: Option D

Solution(By Examveda Team)

$$\eqalign{ & {\text{cose}}{{\text{c}}^2}{60^ \circ } + {\text{se}}{{\text{c}}^2}{60^ \circ } - {\text{co}}{{\text{t}}^2}{60^ \circ } + {\text{ta}}{{\text{n}}^2}{30^ \circ } \cr & = {\left( {\frac{2}{{\sqrt 3 }}} \right)^2} + {\left( 2 \right)^2} - {\left( {\frac{1}{{\sqrt 3 }}} \right)^2} + {\left( {\frac{1}{{\sqrt 3 }}} \right)^2} \cr & = \frac{4}{3} + 4 - \frac{1}{3} + \frac{1}{3} \cr & = \frac{{16}}{3} \cr & = 5\frac{1}{3} \cr} $$

This Question Belongs to Arithmetic Ability >> Trigonometry

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