The value of following is : $$\frac{{\sin \theta .\operatorname{cosec} \theta .\tan \theta .\cot \theta }}{{{{\sin }^2}\theta + {\text{co}}{{\text{s}}^2}\theta }}$$ ?
A. 2
B. 0
C. tanθ
D. 1
Answer: Option D
Solution(By Examveda Team)
$$\eqalign{ & = \frac{{\sin \theta .\operatorname{cosec} \theta .\tan \theta .\cot \theta }}{{{{\sin }^2}\theta + {\text{co}}{{\text{s}}^2}\theta }} \cr & = \frac{{\sin \theta \times \frac{1}{{\sin \theta }} \times \tan \theta \times \frac{1}{{\tan \theta }}}}{1} \cr & = 1 \cr} $$Related Questions on Trigonometry
A. x = -y
B. x > y
C. x = y
D. x < y
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