The value of $$\frac{{{\text{sin 6}}{5^ \circ }}}{{\cos {{25}^ \circ }}}$$ is?
A. 0
B. 1
C. 2
D. No defined
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & = \frac{{{\text{sin 6}}{5^ \circ }}}{{\cos {{25}^ \circ }}} \cr & = \frac{{{\text{sin }}\left( {{{90}^ \circ } - {\text{6}}{5^ \circ }} \right)}}{{\cos {{25}^ \circ }}} \cr & \left[ {\sin \left( {{{90}^ \circ } - \theta } \right) = \cos \theta } \right] \cr & = \frac{{\cos {{25}^ \circ }}}{{\cos {{25}^ \circ }}} \cr & = 1 \cr} $$Related Questions on Trigonometry
A. x = -y
B. x > y
C. x = y
D. x < y
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