Examveda
Examveda

The value of $$\mathop {\lim }\limits_{{\text{x}} \to \infty } {\left( {1 + {{\text{x}}^2}} \right)^{{{\text{e}}^{ - {\text{x}}}}}}$$   is

A. 0

B. $$\frac{1}{2}$$

C. 1

D. $$\infty $$

Answer: Option C


This Question Belongs to Engineering Maths >> Calculus

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