The value of $$\oint\limits_{\text{c}} {\frac{{{{\text{z}}^2}}}{{{{\text{z}}^4} - 1}}{\text{dz}}} $$ using Cauchy's integral formula, around circle |z + 1| = 1 where z = x + iy is
A. 2πi
B. $$ - \pi \frac{{\text{i}}}{2}$$
C. $$ - 3\pi \frac{{\text{i}}}{2}$$
D. π2i
Answer: Option B
This Question Belongs to Engineering Maths >> Complex Variable
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A. -x2 + y2 + constant
B. x2 - y2 + constant
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The product of complex numbers (3 - 2i) and (3 + i4) results in
A. 1 + 6i
B. 9 - 8i
C. 9 + 8i
D. 17 + 6i
If a complex number $${\text{z}} = \frac{{\sqrt 3 }}{2} + {\text{i}}\frac{1}{2}$$ then z4 is
A. $$2\sqrt 2 + 2{\text{i}}$$
B. $$\frac{{ - 1}}{2} + \frac{{{\text{i}}{{\sqrt 3 }^2}}}{2}$$
C. $$\frac{{\sqrt 3 }}{2} - {\text{i}}\frac{1}{2}$$
D. $$\frac{{\sqrt 3 }}{2} - {\text{i}}\frac{1}{8}$$
A. 2πnj
B. 0
C. $$\frac{{\pi {\text{j}}}}{{2\pi }}$$
D. 2πn
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