ExamVeda
Login
Home
This question belongs to Arithmetic Ability Trigonometry
Trigonometry
?

The value of sec228° - cot262° + sin260° + cosec230° is equal to:

Answer & Solution
Correct Answer: Option D
$$\eqalign{ & {\sec ^2}{28^ \circ } - {\cot ^2}{62^ \circ } + {\sin ^2}{60^ \circ } + {\text{cose}}{{\text{c}}^2}{30^ \circ } \cr & = {\sec ^2}{28^ \circ } - {\tan ^2}{28^ \circ } + {\sin ^2}{60^ \circ } + {\text{cose}}{{\text{c}}^2}{30^ \circ } \cr & = 1 + {\left( {\frac{{\sqrt 3 }}{2}} \right)^2} + {\left( 2 \right)^2} \cr & = 1 + \frac{3}{4} + 4 \cr & = \frac{{23}}{4} \cr} $$
Examveda
Question posted by Examveda
Community

Join the Discussion

No comments yet Be the first to discuss this question.