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The value of sec228° - cot262° + sin260° + cosec230° is equal to:
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& {\sec ^2}{28^ \circ } - {\cot ^2}{62^ \circ } + {\sin ^2}{60^ \circ } + {\text{cose}}{{\text{c}}^2}{30^ \circ } \cr
& = {\sec ^2}{28^ \circ } - {\tan ^2}{28^ \circ } + {\sin ^2}{60^ \circ } + {\text{cose}}{{\text{c}}^2}{30^ \circ } \cr
& = 1 + {\left( {\frac{{\sqrt 3 }}{2}} \right)^2} + {\left( 2 \right)^2} \cr
& = 1 + \frac{3}{4} + 4 \cr
& = \frac{{23}}{4} \cr} $$
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