The value of the Integral $$\oint\limits_{\text{c}} {\frac{{ - 3{\text{z}} + 4}}{{\left( {{{\text{z}}^2} + 4{\text{z}} + 5} \right)}}{\text{dz}}} $$ where c is the circle |z| = 1 is given by
A. 0
B. $$\frac{1}{{10}}$$
C. $$\frac{4}{5}$$
D. 1
Answer: Option A
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