Examveda

The value of the integral \[\int_0^{2\pi } {\left( {\frac{3}{{9 + {{\sin }^2}\theta }}} \right){\text{d}}\theta } \]     is

A. \[\frac{{2\pi }}{{\sqrt {10} }}\]

B. \[2\sqrt {10} \pi \]

C. \[\sqrt {10} \pi \]

D. \[2\pi \]

Answer: Option A


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