Examveda
Examveda

The velocity of piston in a reciprocating steam engine is given by (where $$\omega $$ = Angular velocity of crank, r = Radius of crank pin circle, $$\theta $$ = Angle turned by crank from inner dead center and n = Ratio of length of connecting rod to the radius of crank)

A. $$\omega {\text{r}}\left( {\sin \theta + \frac{{\sin 2\theta }}{{\text{n}}}} \right)$$

B. $$\omega {\text{r}}\left( {\cos\theta + \frac{{\cos2\theta }}{{\text{n}}}} \right)$$

C. $${\omega ^2}{\text{r}}\left( {\sin \theta + \frac{{\sin 2\theta }}{{\text{n}}}} \right)$$

D. $${\omega ^2}{\text{r}}\left( {\cos\theta + \frac{{\cos2\theta }}{{\text{n}}}} \right)$$

Answer: Option A


This Question Belongs to Mechanical Engineering >> Theory Of Machine

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Comments ( 3 )

  1. Rajan Mech
    Rajan Mech :
    3 years ago

    Diveded by 2n is the right answer

  2. Kudrat Sharma
    Kudrat Sharma :
    4 years ago

    The formula is v = rw(sin theta +( sin 2 theta/ 2n ) )

  3. Kudrat Sharma
    Kudrat Sharma :
    4 years ago

    The formula is v = rw(sin theta +( sin 2 theta/ 2n ) )

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