The volume of an object expressed in spherical co-ordinates is given by \[{\text{V}} = \int_0^{2\pi } {\int_0^{\frac{\pi }{3}} {\int_0^1 {{{\text{r}}^2}\sin \phi \,{\text{dr d}}\phi \,{\text{d}}\theta .} } } \]
The value of the integral is
A. \[\frac{\pi }{3}\]
B. \[\frac{\pi }{6}\]
C. \[\frac{{2\pi }}{3}\]
D. \[\frac{\pi }{4}\]
Answer: Option A

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