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The volume of the water in two tanks, A and B, is in the ratio of 6 : 5. The volume of water in tank A is increased by 30%. By what percentage should the volume of water in tank B be increased so that both the tanks have the same volume of water?

A. 56%

B. 18%

C. 15%

D. 30%

Answer: Option A

Solution(By Examveda Team)

A : B = 6 : 5
Let A = 600, B = 500
After 30% increased A = 780
We have to increase = 280
Increase% $$ = \frac{{280}}{{500}} \times 100 = 56\% $$

This Question Belongs to Arithmetic Ability >> Percentage

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