There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?
A. $$\frac{{6}}{{7}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{3}}{{8}}$$
D. $$\frac{{5}}{{9}}$$
Answer: Option C
Solution (By Examveda Team)
Total cases of checking in the hotels = $${4^3}$$ ways.Cases, when 3 men are checking in different hotels = 4 × 3 × 2 = 24 ways.
Required probability:
$$\eqalign{ & = \frac{{24}}{{{4^3}}} \cr & = \frac{3}{8} \cr} $$
This Question Belongs to Arithmetic Ability >> Probability
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